Subscription.fromJson constructor

Subscription.fromJson(
  1. Map json_
)

Implementation

Subscription.fromJson(core.Map json_)
  : this(
      archived: json_['archived'] as core.bool?,
      basePlans:
          (json_['basePlans'] as core.List?)
              ?.map(
                (value) => BasePlan.fromJson(
                  value as core.Map<core.String, core.dynamic>,
                ),
              )
              .toList(),
      listings:
          (json_['listings'] as core.List?)
              ?.map(
                (value) => SubscriptionListing.fromJson(
                  value as core.Map<core.String, core.dynamic>,
                ),
              )
              .toList(),
      packageName: json_['packageName'] as core.String?,
      productId: json_['productId'] as core.String?,
      restrictedPaymentCountries:
          json_.containsKey('restrictedPaymentCountries')
              ? RestrictedPaymentCountries.fromJson(
                json_['restrictedPaymentCountries']
                    as core.Map<core.String, core.dynamic>,
              )
              : null,
      taxAndComplianceSettings:
          json_.containsKey('taxAndComplianceSettings')
              ? SubscriptionTaxAndComplianceSettings.fromJson(
                json_['taxAndComplianceSettings']
                    as core.Map<core.String, core.dynamic>,
              )
              : null,
    );