DebugInfo.fromJson constructor

DebugInfo.fromJson(
  1. Object? j
)

Implementation

factory DebugInfo.fromJson(Object? j) {
  final json = j as Map<String, Object?>;
  return DebugInfo(
    stackEntries: switch (json['stackEntries']) {
      null => [],
      List<Object?> $1 => [for (final i in $1) decodeString(i)],
      _ => throw const FormatException('"stackEntries" is not a list'),
    },
    detail: switch (json['detail']) {
      null => '',
      Object $1 => decodeString($1),
    },
  );
}