PhpSettings.fromJson constructor

PhpSettings.fromJson(Object? j)

Implementation

factory PhpSettings.fromJson(Object? j) {
  final json = j as Map<String, Object?>;
  return PhpSettings(
    common: switch (json['common']) {
      null => null,
      Object $1 => CommonLanguageSettings.fromJson($1),
    },
    libraryPackage: switch (json['libraryPackage']) {
      null => '',
      Object $1 => decodeString($1),
    },
  );
}