send method

  1. @override
Future<void> send({
  1. required List<int> value,
  2. Duration durationTimeOut = const Duration(minutes: 1),
  3. Duration durationDelay = const Duration(milliseconds: 1),
})
override

Implementation

@override
Future<void> send(
    {required List<int> value,
    Duration durationTimeOut = const Duration(minutes: 1),
    Duration durationDelay = const Duration(milliseconds: 1)}) async {
  return;
}