postException static method

Future<void> postException({
  1. required dynamic message,
  2. required dynamic detail,
  3. dynamic type,
  4. Map<String, dynamic>? extra,
})

上报自定义异常

Implementation

static Future<void> postException({
  required dynamic message,
  required dynamic detail,
  dynamic type,
  Map<String, dynamic>? extra,
}) => FlutterTencentBuglyPlatform.instance.postException(message: message, detail: detail, type: type, extra: extra);