debug static method

void debug(
  1. String message, [
  2. Object? error,
  3. StackTrace? stackTrace
])

Log debug message

Implementation

static void debug(String message, [Object? error, StackTrace? stackTrace]) {
  if (_level.index <= PaygateLogLevel.debug.index) {
    developer.log(
      message,
      name: '$_prefix.DEBUG',
      error: error,
      stackTrace: stackTrace,
    );
  }
}