toOutlines method
Generate the list of rectangle segments formed from the locus of this line
Use the optional overlap
argument to set the behaviour of the joints
between segments:
- -1: joined by closest corners (largest gap)
- 0 (default): joined by centers (equal gap and overlap)
- 1 (as downloaded): joined by further corners (largest overlap)
Implementation
List<List<LatLng>> toOutlines([int overlap = 0]) {
if (overlap < -1 || overlap > 1) {
throw ArgumentError('`overlap` must be between -1 and 1 inclusive');
}
const Distance dist = Distance();
final int rad = (radius * math.pi / 4).round();
return line.map((pos) {
if ((line.indexOf(pos) + 1) >= line.length) return [LatLng(0, 0)];
final List<LatLng> section = [pos, line[line.indexOf(pos) + 1]];
final double bearing = dist.bearing(section[0], section[1]);
final double clockwiseRotation =
(90 + bearing) > 360 ? 360 - (90 + bearing) : (90 + bearing);
final double anticlockwiseRotation =
(bearing - 90) < 0 ? 360 + (bearing - 90) : (bearing - 90);
final LatLng offset1 =
dist.offset(section[0], rad, clockwiseRotation); // Top-right
final LatLng offset2 =
dist.offset(section[1], rad, clockwiseRotation); // Bottom-right
final LatLng offset3 =
dist.offset(section[1], rad, anticlockwiseRotation); // Bottom-left
final LatLng offset4 =
dist.offset(section[0], rad, anticlockwiseRotation); // Top-left
if (overlap == 0) return [offset1, offset2, offset3, offset4];
final bool r = overlap == -1;
final bool os = line.indexOf(pos) == 0;
final bool oe = line.indexOf(pos) == line.length - 2;
return [
os ? offset1 : dist.offset(offset1, r ? rad : -rad, bearing),
oe ? offset2 : dist.offset(offset2, r ? -rad : rad, bearing),
oe ? offset3 : dist.offset(offset3, r ? -rad : rad, bearing),
os ? offset4 : dist.offset(offset4, r ? rad : -rad, bearing),
];
}).toList()
..removeLast();
}