topProblems method

List<PrioritizedGroup> topProblems(
  1. List<PrioritizedGroup> sorted, {
  2. int limit = 10,
})

Returns the top limit rules from the sorted list (default 10). Ordering already respects priority-before-count.

Implementation

List<PrioritizedGroup> topProblems(
  List<PrioritizedGroup> sorted, {
  int limit = 10,
}) =>
    sorted.take(limit).toList();