getFactors method
Implementation
Iterable<num> getFactors(int len) {
var factors = List<num>.filled(len,0);
var factor = 2 * math.pi / (len - 1);
for (int i = 0; i < len; i++)
factors[i] = 0.54 - 0.46 * math.cos(i * factor);
return factors;
}