show method

Future<void> show({
  1. required BuildContext context,
  2. required FFView<Watched, FFState, ViewModel, Controller> view,
  3. required FFPresentationType asType,
})

Implementation

Future<void> show({
  required BuildContext context,
  required FFView<Watched, FFState, ViewModel, Controller> view,
  required FFPresentationType asType,
}) => showUnsafe(context: context, view: view, asType: asType);