parseJsonInt function
Flexible JSON value parsers — APIs often return numbers as strings.
Implementation
int parseJsonInt(dynamic value, [int defaultValue = 0]) {
if (value == null) return defaultValue;
if (value is int) return value;
if (value is num) return value.toInt();
if (value is String) return int.tryParse(value) ?? defaultValue;
return defaultValue;
}