selectMany<U> method
Implementation
Iterable<U> selectMany<U>(TFuncMapper<T, Iterable<U>> funcMapper) {
List<U> lst = [ ];
this.filterNull().forEach((x) => lst.addAll(funcMapper(x)));
return lst;
}
Iterable<U> selectMany<U>(TFuncMapper<T, Iterable<U>> funcMapper) {
List<U> lst = [ ];
this.filterNull().forEach((x) => lst.addAll(funcMapper(x)));
return lst;
}