selectMany<U> method

Iterable<U> selectMany<U>(
  1. TFuncMapper<T, Iterable<U>> funcMapper
)

Implementation

Iterable<U> selectMany<U>(TFuncMapper<T, Iterable<U>> funcMapper) {
	List<U> lst = [ ];
	this.filterNull().forEach((x) => lst.addAll(funcMapper(x)));
	return lst;
}