toMap method

Map<String, dynamic> toMap(
  1. String firstSplit, {
  2. String secondSplit = "",
  3. bool? isDecode,
})

根据连接字符拼接的字符串转换成map 示例:"siteId=2&positionValue=71" firstSplit一级分隔符 secondSplit二级分隔符 isDecodevalue是否需要Uri.decodeComponent解码

Implementation

Map<String, dynamic> toMap(String firstSplit,
    {String secondSplit = "", bool? isDecode}) {
  var map = LinkedHashMap<String, dynamic>();
  if (this.isNotEmptyString && firstSplit.isNotEmptyString) {
    var list = this.split(firstSplit);
    list.forEach((element) {
      if (element.isNotEmptyString) {
        var entry = element.toMapEntry(secondSplit, isDecode ?? false);
        if (entry != null) {
          map[entry.key] = entry.value;
        }
      }
    });
  }
  return map;
}