setRange method
Writes some elements of iterable into a range of this list.
Copies the objects of iterable, skipping skipCount objects first,
into the range from start, inclusive, to end, exclusive, of this list.
final list1 = <int>[1, 2, 3, 4];
final list2 = <int>[5, 6, 7, 8, 9];
// Copies the 4th and 5th items in list2 as the 2nd and 3rd items
// of list1.
const skipCount = 3;
list1.setRange(1, 3, list2, skipCount);
print(list1); // [1, 8, 9, 4]
The provided range, given by start and end, must be valid.
A range from start to end is valid if 0 ≤ start ≤ end ≤ length.
An empty range (with end == start) is valid.
The iterable must have enough objects to fill the range from start
to end after skipping skipCount objects.
If iterable is this list, the operation correctly copies the elements
originally in the range from skipCount to skipCount + (end - start) to
the range start to end, even if the two ranges overlap.
If iterable depends on this list in some other way, no guarantees are
made.
Implementation
@override
void setRange(int start, int end, Iterable<T> iterable, [int skipCount = 0]) => list.setRange(
length - end, length - start, iterable.skip(skipCount).take(end - start).toList().reversed);