operator >= method
Whether other
index is numerically greater than or equal to this number.
If either operand is the double NaN, the result is always false.
Implementation
bool operator >=(LicenseDescriptor<T> other) => index >= other.index;
Whether other
index is numerically greater than or equal to this number.
If either operand is the double NaN, the result is always false.
bool operator >=(LicenseDescriptor<T> other) => index >= other.index;