recentJankyCount method

int recentJankyCount({
  1. int window = 60,
})

Implementation

int recentJankyCount({int window = 60}) {
  final recent = _samples.length > window
      ? _samples.sublist(_samples.length - window)
      : _samples;
  return recent.where((s) => s.isJanky).length;
}