min constructor
const
min(])
Compare and return minimum value for up to 10 values, returns double.
Implementation
const min(num a, num b, [num c = double.infinity, num d = double.infinity, num e = double.infinity, num f = double.infinity, num g = double.infinity, num h = double.infinity, num i = double.infinity, num j = double.infinity])
: _v =
(a <= b && a <= c && a <= d && a <= e && a <= f && a <= g && a <= h && a <= i && a <= j)
? a * 1.0
: (b <= c && b <= d && b <= e && b <= f && b <= g && b <= h && b <= i && b <= j)
? b * 1.0
: (c <= d && c <= e && c <= f && c <= g && c <= h && c <= i && c <= j)
? c * 1.0
: (d <= e && d <= f && d <= g && d <= h && d <= i && d <= j)
? d * 1.0
: (e <= f && e <= g && e <= h && e <= i && e <= j)
? e * 1.0
: (f <= g && f <= h && f <= i && f <= j)
? f * 1.0
: (g <= h && g <= i && g <= j)
? g * 1.0
: (h <= i && h <= j)
? h * 1.0
: (i <= j)
? i * 1.0
: j * 1.0;