kgetDayOfYear method
在今年的第几天
Implementation
int kgetDayOfYear() {
var file = this;
int month = file.month;
int days = file.day;
for (int i = 1; i < month; i++) {
days = days + (_monthDay[i] ?? 0);
}
if (kisLeapYear() && month > 2) {
days = days + 1;
}
return days;
}