onInitialize method
Callback when this executor is initialized. Returns true if successfully initialized, false otherwise.
Note that this is a non-async method and should hence be 'light-weight' and not block execution for a long duration.
Implementation
@override
bool onInitialize() {
_group.add(_controller.stream);
// get the trigger executor and initialize with this task control executor
if (ExecutorFactory().getTriggerExecutor(taskControl.triggerId) == null) {
triggerExecutor = ExecutorFactory()
.createTriggerExecutor(taskControl.triggerId, trigger);
triggerExecutor?.initialize(trigger, deployment);
}
triggerExecutor =
ExecutorFactory().getTriggerExecutor(taskControl.triggerId);
triggerExecutor?.triggerEvents.listen((_) => onTrigger());
// get the task executor and add the measurements it collects to the stream group
taskExecutor = ExecutorFactory().getTaskExecutor(task);
taskExecutor?.initialize(task, deployment);
_group.add(taskExecutor!.measurements);
return true;
}