leaveRoom method

FutureOr<int> leaveRoom()

@detail api @author shenpengliang @brief Leaves the RTC room.
The user calls this method to leave the room, end the call process, and release all call-related resources. @return - 0: Success. If the user is a host: - The other participants receive rtcRoom:onUserLeave:reason:{@link #ByteRTCRoomDelegate#rtcRoom:onUserLeave:reason} callback. - The publishing streams stop and the other participants receive notifications of the stream states via rtcRoom:onVideoPublishStateChanged:info:state:reason:{@link #ByteRTCRoomDelegate#rtcRoom:onVideoPublishStateChanged:info:state:reason}, rtcRoom:onAudioPublishStateChanged:info:state:reason:{@link #ByteRTCRoomDelegate#rtcRoom:onAudioPublishStateChanged:info:state:reason}. - < 0 : Fail. See ByteRTCReturnStatus{@link #ByteRTCReturnStatus} for more details @note - After the user leaves the room, the local will receive a callback for rtcRoom:onRoomStateChanged:withUid:state:extraInfo:{@link #ByteRTCRoomDelegate#rtcRoom:onRoomStateChanged:withUid:state:extraInfo}; - Call setUserVisibility:{@link #ByteRTCRoom#setUserVisibility} method sets itself to be visible. After the user leaves the room, other users in the room will receive rtcRoom:onUserLeave:reason:{@link #ByteRTCRoomDelegate#rtcRoom:onUserLeave:reason} callback notification.

Implementation

FutureOr<int> leaveRoom() async {
  return await nativeCall('leaveRoom', []);
}