VocabularyFilterInfo.fromJson constructor

VocabularyFilterInfo.fromJson(
  1. Map<String, dynamic> json
)

Implementation

factory VocabularyFilterInfo.fromJson(Map<String, dynamic> json) {
  return VocabularyFilterInfo(
    languageCode: (json['LanguageCode'] as String?)?.toLanguageCode(),
    lastModifiedTime: timeStampFromJson(json['LastModifiedTime']),
    vocabularyFilterName: json['VocabularyFilterName'] as String?,
  );
}