kepler1 function
Solves Kepler's equation by simple iteration.
E₁ = M + e·sin(E₀)
May fail to converge for some values of e and m.
Implementation
double kepler1(double e, double m, {int places = 8}) {
return decimalPlaces(
(e0) => m + e * math.sin(e0),
m,
places: places,
maxIterations: places * 5,
);
}