deserialize method
Implementation
@override
void deserialize(Map<String, dynamic>? json) {
if (json == null) {
throw ApiException(
400, 'Failed to deserialize TableResponse data model.');
}
super.deserialize(json);
if (json.containsKey('RequestId')) {
requestId = json['RequestId'] as String;
} else {
requestId = null;
}
if (json.containsKey('Table')) {
table = ModelBase.createInstance<Table>(
json['Table'] as Map<String, dynamic>);
} else {
table = null;
}
}