deserialize method
void
deserialize(
- Map<String, dynamic>? json
)
override
Implementation
@override
void deserialize(Map<String, dynamic>? json) {
if (json == null) {
throw ApiException(400, 'Failed to deserialize FileLink data model.');
}
super.deserialize(json);
if (json.containsKey('Href')) {
href = json['Href'] as String;
} else {
href = null;
}
if (json.containsKey('Rel')) {
rel = json['Rel'] as String;
} else {
rel = null;
}
if (json.containsKey('Title')) {
title = json['Title'] as String;
} else {
title = null;
}
if (json.containsKey('Type')) {
type = json['Type'] as String;
} else {
type = null;
}
}