deserialize method

  1. @override
void deserialize(
  1. Map<String, dynamic>? json
)
override

Implementation

@override
void deserialize(Map<String, dynamic>? json) {
  if (json == null) {
    throw ApiException(400, 'Failed to deserialize FieldUpdate data model.');
  }

  super.deserialize(json);
  if (json.containsKey('LocaleId')) {
    localeId = json['LocaleId'] as String;
  } else {
    localeId = null;
  }

  if (json.containsKey('FieldCode')) {
    fieldCode = json['FieldCode'] as String;
  } else {
    fieldCode = null;
  }
}