sendFlutterException method

Future<void> sendFlutterException(
  1. FlutterErrorDetails flutterErrorDetails, {
  2. bool isFatal = true,
})

Implementation

Future<void> sendFlutterException(FlutterErrorDetails flutterErrorDetails,{bool isFatal = true}) async {
  FlutterError.presentError(flutterErrorDetails);
  sendException(flutterErrorDetails.exceptionAsString(), flutterErrorDetails.stack, isFatal: isFatal);
}