openSystemApp method

  1. @override
Future<void> openSystemApp(
  1. String appName
)
override

Open a specific system application.

Implementation

@override
Future<void> openSystemApp(String appName) async {
  try {
    await methodChannel.invokeMethod('openSystemApp', {
      'appName': appName,
    });
  } on PlatformException catch (e) {
    throw Exception('Failed to open system app: ${e.message}');
  }
}