launchApp method

@override Future<void> launchApp(String packageName)

Launch an app with a given package name.

Implementation

@override
Future<void> launchApp(String packageName) async {
  try {
    await methodChannel.invokeMethod('launchApp', {
      'packageName': packageName,
    });
  } on PlatformException catch (e) {
    throw Exception('Failed to launch app: ${e.message}');
  }
}