sendUnsafe method

Future<ApiResponse> sendUnsafe(
  1. BaseRequest request
)

Send request and return the response.

Implementation

Future<ApiResponse> sendUnsafe(BaseRequest request) async {
  final response = await inner.send(_ApiRequest(this, request));

  if (response.statusCode >= 200 && response.statusCode < 300) {
    return handleSuccess(
      await SuccessApiResponse.fromResponse(request, response),
    );
  }

  return handleError(await ErrorApiResponse.fromResponse(request, response));
}