lastIndexOf method

  1. @override
int lastIndexOf(
  1. T element, [
  2. int? start
])
override

The last index of element in this list.

Searches the list backwards from index start to 0.

The first time an object o is encountered so that o == element, the index of o is returned.

final notes = <String>['do', 're', 'mi', 're'];
const startIndex = 2;
final index = notes.lastIndexOf('re', startIndex); // 1

If start is not provided, this method searches from the end of the list.

final notes = <String>['do', 're', 'mi', 're'];
final index = notes.lastIndexOf('re'); // 3

Returns -1 if element is not found.

final notes = <String>['do', 're', 'mi', 're'];
final index = notes.lastIndexOf('fa'); // -1

Implementation

@override
int lastIndexOf(T element, [int? start]) {
  for (final e in _list.getRange(_start, _end).indexed.skip(start ?? 0)) {
    if (e.$2 == element) {
      return e.$1;
    }
  }
  return -1;
}