deserializeList method

List<T> deserializeList(
  1. List<List> it
)

Implementation

List<T> deserializeList(List<List<dynamic>> it) {
  var optResult = it.map(deserialize).toList();
  var result = <T>[];
  for (var element in optResult) {
    element.ifPresent((item) {
      result.add(item);
    });
  }

  return result;
}