sendInputData method

  1. @override
Future<String?> sendInputData(
  1. List<int> input
)
override

Implementation

@override
Future<String?> sendInputData(List<int> input) async {
  try {
    final out = await methodChannel.invokeMethod('sendData', {
      "inputData": input,
    });
    debugPrint("Data sent $input $out");
    return out;
  } on PlatformException catch (e) {
    debugPrint("Failed: ${e.message}");
    return "Error";
  }
}