turnOnIOSDebug method

@override Future<Map> turnOnIOSDebug()

开启 iOS debug 日志

Implementation

@override
Future<Map<dynamic, dynamic>> turnOnIOSDebug() async {
  if (!Platform.isIOS) {
    return {
      'code': kAliyunPushOnlyIOS,
      'errorMsg': 'Only support iOS',
    };
  }

  Map<dynamic, dynamic> result =
      await methodChannel.invokeMethod('turnOnDebug');
  return result;
}