longestCommonSubsequenceLengthOf function
Returns the length of the longest common subsequence of two strings.
Parameters
source
andtarget
are two strings.- if
ignoreCase
is true, the character case shall be ignored. - if
ignoreWhitespace
is true, space, tab, newlines etc whitespace characters will be ignored. - if
ignoreNumbers
is true, numbers will be ignored. - if
alphaNumericOnly
is true, only letters and digits will be matched.
TIPS: You can pass both
ignoreNumbers
andalphaNumericOnly
to true to ignore everything else except letters.
Details
Common subsequence between two strings is a set of characters appearing in both in the same order. Unlike substrings, the subsequences are not required occupy consecutive positions.
This functions returns the length of the longest common subsequence between
source
and target
without modifying their contents.
This is similar to Levenshtein distance, where only insertion and deletion operations are permitted, and substitution is not.
If n
is the length of source
and m
is the length of target
,
Complexity: Time O(nm)
| Space O(n)
Implementation
int longestCommonSubsequenceLengthOf(
String source,
String target, {
bool ignoreCase = false,
bool ignoreWhitespace = false,
bool ignoreNumbers = false,
bool alphaNumericOnly = false,
}) {
source = cleanupString(
source,
ignoreCase: ignoreCase,
ignoreWhitespace: ignoreWhitespace,
ignoreNumbers: ignoreNumbers,
alphaNumericOnly: alphaNumericOnly,
);
target = cleanupString(
target,
ignoreCase: ignoreCase,
ignoreWhitespace: ignoreWhitespace,
ignoreNumbers: ignoreNumbers,
alphaNumericOnly: alphaNumericOnly,
);
return longestCommonSubsequenceLength(source.codeUnits, target.codeUnits);
}