newtonIteration function

BigInt newtonIteration(
  1. BigInt n,
  2. BigInt x0
)

Implementation

BigInt newtonIteration(BigInt n, BigInt x0) {
  final x1 = (BigInt.from(n / x0) + x0) >> 1;
  if (x0 == x1 || x0 == (x1 - BigInt.from(1))) {
    return x0;
  }
  return newtonIteration(n, x1);
}