sendRequest method

Future<String> sendRequest(
  1. Uri url
)

sends the request to the specified url

Implementation

Future<String> sendRequest(Uri url) async {
  http.Response response = await http.get(url);
  if (response.statusCode != 200) {
    throw Exception('Failed to fetch data from Aare.guru API, '
        'status code: ${response.statusCode} ${response.reasonPhrase}');
  }
  print(response.request?.url);
  return response.body;
}