membersStream property
Channel members list as a stream.
Implementation
Stream<List<Member>> get membersStream => CombineLatestStream.combine2<
List<Member?>?, Map<String?, User?>, List<Member>>(
channelStateStream.map((cs) => cs.members),
_channel.client.state.usersStream,
(members, users) =>
members!.map((e) => e!.copyWith(user: users[e.user!.id])).toList(),
).distinct(const ListEquality().equals);