startWithMany method

Observable<T> startWithMany (
  1. List<T> startValues
)
inherited

Prepends a sequence of values to the source Observable.

Example

new Observable.just(3).startWithMany([1, 2])
  .listen(print); // prints 1, 2, 3

Implementation

Observable<T> startWithMany(List<T> startValues) =>
    transform(StartWithManyStreamTransformer<T>(startValues));