EaseCircInOut method
Circular In Out
Implementation
double EaseCircInOut(num t, num b, num c, num d)
{
if ((t/=d/2.0) < 1.0) {
return (-c/2.0*(math.sqrt(1.0 - t*t) - 1.0) + b);
}
t -= 2.0;
return (c/2.0*(math.sqrt(1.0 - t*t) + 1.0) + b);
}