lastIndexOf method

  1. @override
int lastIndexOf(
  1. Object? element, [
  2. int? start
])
override

The last index of element in this list.

Searches the list backwards from index start to 0.

The first time an object o is encountered so that o == element, the index of o is returned.

final notes = <String>['do', 're', 'mi', 're'];
const startIndex = 2;
final index = notes.lastIndexOf('re', startIndex); // 1

If start is not provided, this method searches from the end of the list.

final notes = <String>['do', 're', 'mi', 're'];
final index = notes.lastIndexOf('re'); // 3

Returns -1 if element is not found.

final notes = <String>['do', 're', 'mi', 're'];
final index = notes.lastIndexOf('fa'); // -1

Implementation

@override
int lastIndexOf(Object? element, [int? start]) {
  if (element != value) {
    return -1;
  }
  if (start == null) {
    return length - 1;
  }
  if (start < 0 || start > length) {
    return length - 1;
  } else {
    return start;
  }
}