PropertyFilter.fromJson constructor

PropertyFilter.fromJson(Map _json)

Implementation

PropertyFilter.fromJson(core.Map _json) {
  if (_json.containsKey("op")) {
    op = _json["op"];
  }
  if (_json.containsKey("property")) {
    property = new PropertyReference.fromJson(_json["property"]);
  }
  if (_json.containsKey("value")) {
    value = new Value.fromJson(_json["value"]);
  }
}