decodeStream method

Future<T> decodeStream(Stream<List<int>> stream)

Decode a single value from stream.

This is equivalent to calling type.decode(await stream.expand((bytes) => bytes).toList()), but may be significantly more efficient as the binary blob does not need to be stored in memory until all data is received.

Implementation

Future<T> decodeStream(Stream<List<int>> stream) =>
    stream.transform(decoder).single;